Reference to non-static member function must be called(必须调用非静态成员函数的引用)
问题描述
我使用的是 C++(不是 C++11).我需要创建一个指向类中函数的指针.我尝试执行以下操作:
I'm using C++ (not C++11). I need to make a pointer to a function inside a class. I try to do following:
void MyClass::buttonClickedEvent( int buttonId ) {
// I need to have an access to all members of MyClass's class
}
void MyClass::setEvent() {
void ( *func ) ( int );
func = buttonClickedEvent; // <-- Reference to non static member function must be called
}
setEvent();
但是有一个错误:必须调用对非静态成员函数的引用".我应该怎么做才能指向 MyClass 的成员?
But there's an error: "Reference to non static member function must be called". What should I do to make a pointer to a member of MyClass?
推荐答案
问题在于 buttonClickedEvent
是一个成员函数,你需要一个指向 member 的指针才能调用它.
The problem is that buttonClickedEvent
is a member function and you need a pointer to member in order to invoke it.
试试这个:
void (MyClass::*func)(int);
func = &MyClass::buttonClickedEvent;
然后当你调用它时,你需要一个 MyClass
类型的对象来这样做,例如 this
:
And then when you invoke it, you need an object of type MyClass
to do so, for example this
:
(this->*func)(<argument>);
http://www.codeguru.com/cpp/cpp/article.php/c17401/C-Tutorial-PointertoMember-Function.htm
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