如何在 C++ 中通过引用返回类对象?-C/C++问题

How to return a class object by reference in C++?(如何在 C++ 中通过引用返回类对象?)

本文介绍了如何在 C++ 中通过引用返回类对象?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

我有一个名为 Object 的类，用于存储一些数据.

I have a class called Object which stores some data.

我想使用这样的函数通过引用返回它:

I would like to return it by reference using a function like this:

    Object& return_Object();

然后，在我的代码中，我会这样称呼它:

Then, in my code, I would call it like this:

    Object myObject = return_Object();

我已经编写了这样的代码并且它可以编译.但是，当我运行代码时，我始终遇到段错误.通过引用返回类对象的正确方法是什么?

I have written code like this and it compiles. However, when I run the code, I consistently get a seg fault. What is the proper way to return a class object by reference?

推荐答案

您可能正在返回堆栈上的对象.也就是说，return_Object() 可能看起来像这样:

You're probably returning an object that's on the stack. That is, return_Object() probably looks like this:

Object& return_Object()
{
    Object object_to_return;
    // ... do stuff ...

    return object_to_return;
}

如果这是你正在做的事情，那你就不走运了 - object_to_return 已经超出范围并在 return_Object 的末尾被破坏，所以 myObject 指的是一个不存在的对象.您要么需要按值返回，要么返回在更广泛范围内声明的 Object 或 new 到堆上.

If this is what you're doing, you're out of luck - object_to_return has gone out of scope and been destructed at the end of return_Object, so myObject refers to a non-existent object. You either need to return by value, or return an Object declared in a wider scope or newed onto the heap.

这篇关于如何在 C++ 中通过引用返回类对象?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！