Multiply char by integer (c++)(将 char 乘以整数 (c++))
问题描述
char 可以乘 int 吗?
Is it possible to multiply a char by an int?
例如,我正在尝试制作一个图表,每次出现一个数字时都带有 *.
For example, I am trying to make a graph, with *'s for each time a number occurs.
类似的东西,但这不起作用
So something like, but this doesn't work
char star = "*";
int num = 7;
cout << star * num //to output 7 stars
推荐答案
我不会称该操作为乘法",这只是令人困惑.串联是一个更好的词.
I wouldn't call that operation "multiplication", that's just confusing. Concatenation is a better word.
无论如何,名为 std::string
的 C++ 标准字符串类有一个非常适合您的构造函数.
In any case, the C++ standard string class, named std::string
, has a constructor that's perfect for you.
string ( size_t n, char c );
内容被初始化为由字符c
、n
次重复形成的字符串.
Content is initialized as a string formed by a repetition of character c
, n
times.
所以你可以这样:
char star = '*';
int num = 7;
std::cout << std::string(num, star) << std::endl;
确保包含相关的标题,<string>
.
Make sure to include the relevant header, <string>
.
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本文标题为:将 char 乘以整数 (c++)


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