在 Newtonsoft.Json 库中获取原始 json 字符串

Get Raw json string in Newtonsoft.Json Library(在 Newtonsoft.Json 库中获取原始 json 字符串)

问题描述

我有这样的json

{
    "name": "somenameofevent",
    "type": "event",
    "data": {
        "object": {
            "age": "18",
            "petName": "18"
        },
        "desct": {
        }
    }
}

我有 2 个这样的对象

and I have 2 objects like this

public class CustEvent
{
    [JsonProperty("name")]
    public string Name { get; set; }
    [JsonProperty("type")]
    public string EventType{ get; set; }
    [JsonProperty("data")]
    public SomeData Data{ get; set; }
}

public class SomeData
{
    [JsonProperty("object")]
    public String SomeObject { get; set;}
    [JsonProperty("dsct")]
    public String SomeDesct { get; set; }
}

我使用将 json 解析为对象 Newtonsoft.NET 库.以及如何将 RAW JSON 转换为 SomeObject 、 SomeDesct 属性?在 JSON 中，data.object ..."是复杂对象，我只想获取这些属性的原始 JSON 字符串.你能帮帮我吗?

I use to parse json to object Newtonsoft.NET library. And how i can get RAW JSON into SomeObject , SomeDesct properties ? In JSON "data.object ..." are complex object and i want to get only RAW JSON String to those properties. Can you help me ?

推荐答案

您不需要编写任何转换器， 只需使用 JRaw 输入如下:

You don't need to write any converters, just use the JRaw type as follows:

public class SomeData
{
    [JsonProperty("object")]
    public JRaw SomeObject { get; set;}
    [JsonProperty("dsct")]
    public JRaw SomeDesct { get; set; }
}

然后您可以通过检查 .Value 属性来访问原始值:

Then you can access the raw value by checking the .Value property:

var rawJsonDesct = (string)data.SomeDesct.Value;

如果您想保留 string 签名，只需将 JSON 序列化为隐藏属性，然后在访问器调用中进行字符串转换即可.

If you want to retain the string signature, just serialize the JSON to a hidden property and have the string conversion in the accessor call instead.

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