获取没有 Content-Disposition 的文件名

Get filename without Content-Disposition(获取没有 Content-Disposition 的文件名)

问题描述

我几天来一直在寻找这个问题的解决方案，但我找不到任何解决方案.

I am looking for a solution for this problem for days and I can't find any.

我想通过网络客户端从网络服务器下载文件.下载工作正常，但我无法获得真实的文件名，这对我来说非常重要.

I want to download a file from a webserver with a webclient. The download works fine, but I can't get the real filename, which is very important for me.

我在许多主页上读到，文件名应该保存在 Content-Disposition-Header 中.不幸的是，这个网站的标题是空的.我试图得到它:

I read on many homepages, that the filename should be saved in the Content-Disposition-Header. Unfortunately this header of the site is empty. I tried to get it with:

string header_contentDisposition ="";
using (WebClient client = new WebClient())
            {
                client.OpenRead(link);

                header_contentDisposition = client.ResponseHeaders["Content-Disposition"];
                MessageBox.Show(header_contentDisposition);
            }

此标头内没有保存任何信息.

There is no information saved inside this header.

如果我尝试使用浏览器(IE、Opera、Chrome)下载文件，文件名会显示在文件对话框中，因此必须将其保存在某处.

If I try to download the file with my Browser (IE, Opera, Chrome) the filename gets shown in the filedialog, so it has to be saved somewhere.

你能想象我在哪里可以找到它吗?

Can you imagine where I can find it?

我无法从 URL 中提取它，因为链接是由 php 生成的，例如

I can't extract it from the URL, because the link is generated by php like

http://www.example.com/download.php?id=10

推荐答案

你可以试试这个:

        HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
        try
        {

            HttpWebResponse res = (HttpWebResponse)request.GetResponse();
            using (Stream rstream = res.GetResponseStream())
            {
                string fileName = res.Headers["Content-Disposition"] != null ?
                    res.Headers["Content-Disposition"].Replace("attachment; filename=", "").Replace(""", "") :
                    res.Headers["Location"] != null ? Path.GetFileName(res.Headers["Location"]) : 
                    Path.GetFileName(url).Contains('?') || Path.GetFileName(url).Contains('=') ?
                    Path.GetFileName(res.ResponseUri.ToString()) : defaultFileName;
            }
            res.Close();
        }
        catch { }

在 http://upload.p-kratzer.com/index.php?dir=&file=asdfasdfwervdcvvedb 它确实返回了 wetter.JPG.

Tested this on http://upload.p-kratzer.com/index.php?dir=&file=asdfasdfwervdcvvedb and it does return wetter.JPG.

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