Selecting COUNT(*) with DISTINCT(使用 DISTINCT 选择 COUNT(*))
问题描述
In SQL Server 2005 I have a table cm_production
that lists all the code that's been put into production. The table has a ticket_number
, program_type
, program_name
and push_number
along with some other columns.
GOAL: Count all the DISTINCT program names by program type and push number.
What I have so far is:
DECLARE @push_number INT;
SET @push_number = [HERE_ADD_NUMBER];
SELECT DISTINCT COUNT(*) AS Count, program_type AS [Type]
FROM cm_production
WHERE push_number=@push_number
GROUP BY program_type
This gets me partway there, but it's counting all the program names, not the distinct ones (which I don't expect it to do in that query). I guess I just can't wrap my head around how to tell it to count only the distinct program names without selecting them. Or something.
Count all the DISTINCT program names by program type and push number
SELECT COUNT(DISTINCT program_name) AS Count,
program_type AS [Type]
FROM cm_production
WHERE push_number=@push_number
GROUP BY program_type
DISTINCT COUNT(*)
will return a row for each unique count. What you want is COUNT(DISTINCT <expression>)
: evaluates expression for each row in a group and returns the number of unique, non-null values.
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本文标题为:使用 DISTINCT 选择 COUNT(*)


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