How can I write SQL in Oracle in my case?(在我的情况下,如何在 Oracle 中编写 SQL?)
问题描述
所以,这里是表格-
create table person (
id number,
name varchar2(50)
);
create table injury_place (
id number,
place varchar2(50)
);
create table person_injuryPlace_map (
person_id number,
injury_id number
);
insert into person values (1, 'Adam');
insert into person values (2, 'Lohan');
insert into person values (3, 'Mary');
insert into person values (4, 'John');
insert into person values (5, 'Sam');
insert into injury_place values (1, 'kitchen');
insert into injury_place values (2, 'Washroom');
insert into injury_place values (3, 'Rooftop');
insert into injury_place values (4, 'Garden');
insert into person_injuryPlace_map values (1, 2);
insert into person_injuryPlace_map values (2, 3);
insert into person_injuryPlace_map values (1, 4);
insert into person_injuryPlace_map values (3, 2);
insert into person_injuryPlace_map values (4, 4);
insert into person_injuryPlace_map values (5, 2);
insert into person_injuryPlace_map values (1, 1);
这里,person_injuryPlace_map
表只会映射其他两个表.
Here, table person_injuryPlace_map
will just map the both other tables.
我想要显示数据的方式是 -
How I wanted to show data is -
Kitchen Pct Washroom Pct Rooftop Pct Garden Pct
-----------------------------------------------------------------------
1 14.29% 3 42.86% 1 14.29% 2 28.57%
这里,厨房、洗手间、屋顶、花园柱的值是发生的事件总数.Pct 列将显示占总数的百分比.
Here, the value of Kitchen, Washroom, Rooftop, Garden column is the total incidents happened. Pct columns will show the percentage of the total count.
如何在 Oracle SQL 中执行此操作?
How can I do this in Oracle SQL?
推荐答案
您需要使用标准的 PIVOT 查询.
You need to use the standard PIVOT query.
根据您的 Oracle 数据库版本,您可以通过两种方式进行:
Depending on your Oracle database version, you could do it in two ways:
将 PIVOT 用于 11g 版 及更高版本:
Using PIVOT for version 11g and up:
SQL> SELECT *
2 FROM
3 (SELECT c.place place,
4 row_number() OVER(PARTITION BY c.place ORDER BY NULL) cnt,
5 (row_number() OVER(PARTITION BY c.place ORDER BY NULL)/
6 COUNT(place) OVER(ORDER BY NULL))*100 pct
7 FROM person_injuryPlace_map A
8 JOIN person b
9 ON(A.person_id = b.ID)
10 JOIN injury_place c
11 ON(A.injury_id = c.ID)
12 ORDER BY c.place
13 ) PIVOT (MAX(cnt),
14 MAX(pct) pct
15 FOR (place) IN ('kitchen' AS kitchen,
16 'Washroom' AS Washroom,
17 'Rooftop' AS Rooftop,
18 'Garden' AS Garden));
KITCHEN KITCHEN_PCT WASHROOM WASHROOM_PCT ROOFTOP ROOFTOP_PCT GARDEN GARDEN_PCT
---------- ----------- ---------- ------------ ---------- ----------- ---------- ----------
1 14.2857143 3 42.8571429 1 14.2857143 2 28.5714286
MAX 和 DECODE 用于 10g 版 及之前的版本:
Using MAX and DECODE for version 10g and before:
SQL> SELECT MAX(DECODE(t.place,'kitchen',cnt)) Kitchen ,
2 MAX(DECODE(t.place,'kitchen',pct)) Pct ,
3 MAX(DECODE(t.place,'Washroom',cnt)) Washroom ,
4 MAX(DECODE(t.place,'Washroom',pct)) Pct ,
5 MAX(DECODE(t.place,'Rooftop',cnt)) Rooftop ,
6 MAX(DECODE(t.place,'Rooftop',pct)) Pct ,
7 MAX(DECODE(t.place,'Garden',cnt)) Garden ,
8 MAX(DECODE(t.place,'Garden',pct)) Pct
9 FROM
10 (SELECT b.ID bid,
11 b.NAME NAME,
12 c.ID cid,
13 c.place place,
14 row_number() OVER(PARTITION BY c.place ORDER BY NULL) cnt,
15 ROUND((row_number() OVER(PARTITION BY c.place ORDER BY NULL)/
16 COUNT(place) OVER(ORDER BY NULL))*100, 2) pct
17 FROM person_injuryPlace_map A
18 JOIN person b
19 ON(A.person_id = b.ID)
20 JOIN injury_place c
21 ON(A.injury_id = c.ID)
22 ORDER BY c.place
23 ) t;
KITCHEN PCT WASHROOM PCT ROOFTOP PCT GARDEN PCT
---------- ---------- ---------- ---------- ---------- ---------- ---------- ----------
1 14.29 3 42.86 1 14.29 2 28.57
这篇关于在我的情况下,如何在 Oracle 中编写 SQL?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:在我的情况下,如何在 Oracle 中编写 SQL?


- 更改自动增量起始编号? 2021-01-01
- 在SQL中,如何为每个组选择前2行 2021-01-01
- SQL 临时表问题 2022-01-01
- 远程 mySQL 连接抛出“无法使用旧的不安全身份验证连接到 MySQL 4.1+"来自 XAMPP 的错误 2022-01-01
- 如何将 SonarQube 6.7 从 MySQL 迁移到 postgresql 2022-01-01
- 使用 Oracle PL/SQL developer 生成测试数据 2021-01-01
- 以一个值为轴心,但将一行上的数据按另一行分组? 2022-01-01
- 导入具有可变标题的 Excel 文件 2021-01-01
- 如何将 Byte[] 插入 SQL Server VARBINARY 列 2021-01-01
- 如何使用 pip 安装 Python MySQLdb 模块? 2021-01-01