string cannot be converted to int! how to sum a scanned int on java?(字符串不能转换为int!如何在java上对扫描的int求和?)
问题描述
我编写了这个简单的程序来求和用户写入的扫描 int,但是当我编译它,它说字符串不能转换为int".这个程序有什么问题?
I wrote this simple program to sum a scanned int written by the user, but when i compile it, it says that "string cannot be converted to int." What is wrong in this program?
import java.util.*;
public class Pr6{
public static void main(String[] args){
Scanner scan = new Scanner (System.in);
int num1;
int num2;
int num3;
int sum;
System.out.print("Please write an integer: ");
num1 = scan.nextLine();
System.out.print("Please write an integer: ");
num2 = scan.nextLine();
System.out.print("Please write an integer: ");
num3 = scan.nextLine();
sum = num1 + num2 + num3;
System.out.print("Total = " + sum);
}//main
}//Pr6
推荐答案
这是你的问题
num1 = scan.nextLine();
我们看看num1是什么数据类型:
Let's look at what data type num1 is:
int num1;
scan.nextLine()
将返回一个字符串.而且你不能有 int num1 = "1",因为它们是不同的数据类型.
scan.nextLine()
will return a String. And you can't have int num1 = "1", because they are different data types.
您应该使用 scan.nextInt()
.它将返回一个数字.这会解决你的问题:)
You should use scan.nextInt()
. It will return a number. That'll solve your problems :)
所以你会有 num1 = scan.nextInt()
、num2 = scan.nextInt()
和 num3 = scan.nextInt()代码>.
So you'll have num1 = scan.nextInt()
, num2 = scan.nextInt()
, and num3 = scan.nextInt()
.
我希望这会有所帮助.祝你好运!
I hope that helps. Good luck!
这篇关于字符串不能转换为int!如何在java上对扫描的int求和?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:字符串不能转换为int!如何在java上对扫描的int求


- 将log4j 1.2配置转换为log4j 2配置 2022-01-01
- 从 finally 块返回时 Java 的奇怪行为 2022-01-01
- Jersey REST 客户端:发布多部分数据 2022-01-01
- Safepoint+stats 日志,输出 JDK12 中没有 vmop 操作 2022-01-01
- Eclipse 插件更新错误日志在哪里? 2022-01-01
- C++ 和 Java 进程之间的共享内存 2022-01-01
- Spring Boot连接到使用仲裁器运行的MongoDB副本集 2022-01-01
- Java包名称中单词分隔符的约定是什么? 2022-01-01
- value & 是什么意思?0xff 在 Java 中做什么? 2022-01-01
- 如何使用WebFilter实现授权头检查 2022-01-01