采用整数并返回所有可能的加法格式的算法

Algorithm that takes an integer and returns all possible format of addition(采用整数并返回所有可能的加法格式的算法)

问题描述

我需要编写一个算法，它接受一个整数并返回所有可能的加法格式

I need to write an algorithm that takes an integer and returns all possible format of addition

例如

如果我进入:6

它将返回以下字符串:

 0+6=6
 1+1+1+1+1+1=6
 1+1+1+1+2=6
 1+1+1+3=6
 1+1+4=6
 1+5=6
 2+1+1+1+1=6
 2+1+1+2=6
 2+1+3=6
 2+4=6
 3+1+1+1=6
 3+1+2=6
 3+3=6
 4+1+1=6
 4+2=6
 5+1=6
 6+0=6

这是我的尝试:

import java.util.*;
public class Test
{
    public static void main(String[] args)
    {
        Scanner in = new Scanner(System.in);
        System.out.print("Enter an integer? ");
        int num = in.nextInt();
        System.out.println();
        calculate(num);
    }
    private static void calculate(int n)
    {
        int[] arInt = new int[n];
        for(int i = 0; i <= n; i++)
        {
            for(int j = 0; j <= n; j++)
            {
                arInt[j] = i;
            }
            // ...
        }
    }
}

推荐答案

我同意 Brad.完成此操作的最佳方法可能是通过递归.事实上，我昨晚正在研究与此相关的事情.我使用递归回溯算法解决了我的问题.查看维基百科页面:回溯

I agree with Brad. The best way to complete this would probably be through recursion. In fact, I was working on something related to this last night. I solved my problem using a recursive backtracking algorithm. Check out the Wikipedia page: Backtracking

现在，我不保证没有更好、更简单的方法来解决这个问题.但是，通过递归回溯，您将找到所有解决方案.

Now, I make no guarantees that there aren't better, less complex ways to solve this. However, with recursive backtracking you will find all the solutions.

但有一点需要注意，即 0.您可以将任意数量的零放入加法/减法中，结果会相同.

One thing to watch out for though, that 0. You can throw any amount of zeros into an addition/subtraction and it will come out the same.

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