Java JPopupMenu bug(Java JPopupMenu 错误)
问题描述
好像我在 Java 中发现了一个错误:
Seems like I've found a bug in Java:
我需要创建具有透明背景的 JFrame,现在我需要为某些用户操作显示 JPopupMenu.当 JPopupMenu 完全位于 JFrame 内时,它可以正常工作.但是当 JPopupMenu 部分在 JFrame 之外时,没有项目可见.
I need to create the JFrame with a transparent background and now I need to show the JPopupMenu for some user actions. It works fine when JPopupMenu is housed fully inside a JFrame. But when the JPopupMenu is partly outside the JFrame, no item is visible.
SSCCE:
public class PopupTest {
    public static void main(String[] a) {
        final JFrame frame = new JFrame();
        frame.setSize(500, 500);
        frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        final JPanel panel = new JPanel(new BorderLayout());
        panel.setBorder(BorderFactory.createLineBorder(Color.RED));
        panel.addMouseListener(new MouseAdapter() {
            @Override
            public void mouseClicked(MouseEvent e) {
                if (e.getButton() == MouseEvent.BUTTON3) {
                    JPopupMenu menu = new JPopupMenu();
                    for (int i = 0 ; i < 10; i++) {
                        menu.add(String.valueOf(i));
                    }
                    menu.show(panel, e.getX(), e.getY());
                }
            }
        });
        frame.setContentPane(panel);
        frame.setUndecorated(true);
        frame.setBackground(new Color(50, 50, 50, 200));
        SwingUtilities.invokeLater(new Runnable() {
            @Override
            public void run() {
                frame.setVisible(true);
            }
        });
    }
}
有人知道怎么解决吗?
PS: JDK 7u40,Win x64
PS: JDK 7u40, Win x64
推荐答案
这是Oracle JDK 7中的bug(顺便说一下在Open JDK 7中无法重现).
This is bug in Oracle JDK 7 (it cannot be reproduced in Open JDK 7 by the way).
要解决此问题,您可以制定一种解决方法(是的,这只是一种解决方法,不能保证它不会因某些 Java 更新而中断),以便为弹出菜单创建的窗口将变得不透明,因为它一出现,就会正确显示.最起码到现在.以下是 Java 7 及更高版本的实现方式:
To fix this you can make a workaround (yes, this is just a workaround, there is no guarantees that it won't break with some Java update) so that the window created for popup-menu will become non-opaque as soon as it shows up, then it will be displayed properly. Atleast for now. Here is how this can be done for Java version 7 and later:
PropertyChangeListener propertyChangeListener = new PropertyChangeListener ()
{
    @Override
    public void propertyChange ( final PropertyChangeEvent evt )
    {
        if ( evt.getNewValue () == Boolean.TRUE )
        {
            // Retrieving popup menu window (we won't find it if it is inside of parent frame)
            final Window ancestor = getWindowAncestor ( popupMenu );
            if ( ancestor != null && ancestor.getClass ().getCanonicalName ().endsWith ( "HeavyWeightWindow" ) )
            {
                // Checking that parent window for our window is opaque, only then setting opacity
                final Component parent = ancestor.getParent ();
                if ( parent != null && parent instanceof Window && parent.getBackground ().getAlpha () == 0 )
                {
                    // Making popup menu window non-opaque
                    ancestor.setBackground ( new Color ( 0, 0, 0, 0 ) );
                }
            }
        }
    }
    private Window getWindowAncestor ( Component component )
    {
        if ( component == null )
        {
            return null;
        }
        if ( component instanceof Window )
        {
            return ( Window ) component;
        }
        for ( Container p = component.getParent (); p != null; p = p.getParent () )
        {
            if ( p instanceof Window )
            {
                return ( Window ) p;
            }
        }
        return null;
    }
};
popupMenu.addPropertyChangeListener ( "visible", propertyChangeListener );
如果您还想支持 JDK 6 版本,则必须付出更多努力,因为该代码甚至无法在早期 JDK 版本上编译(在早期版本的 Window 中没有set/getBackground"方法).
You will have to put some more effort if you also want to support JDK 6- versions because that code won't even compile on earlier JDK versions (there are no "set/getBackground" methods in Window in earlier versions).
这篇关于Java JPopupMenu 错误的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:Java JPopupMenu 错误
				
        
 
            
        - Safepoint+stats 日志,输出 JDK12 中没有 vmop 操作 2022-01-01
 - 将log4j 1.2配置转换为log4j 2配置 2022-01-01
 - Eclipse 插件更新错误日志在哪里? 2022-01-01
 - 如何使用WebFilter实现授权头检查 2022-01-01
 - Jersey REST 客户端:发布多部分数据 2022-01-01
 - value & 是什么意思?0xff 在 Java 中做什么? 2022-01-01
 - 从 finally 块返回时 Java 的奇怪行为 2022-01-01
 - C++ 和 Java 进程之间的共享内存 2022-01-01
 - Spring Boot连接到使用仲裁器运行的MongoDB副本集 2022-01-01
 - Java包名称中单词分隔符的约定是什么? 2022-01-01
 
						
						
						
						
						