使用 nextInt 和 nextLine() 时遇到问题-Java问题

Trouble using nextInt and nextLine()(使用 nextInt 和 nextLine() 时遇到问题)

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问题描述

这不是让我输入我的名字，但它确实可以正常工作.我知道我可以更改语句的顺序，但还有其他方法可以做到吗?

It's not letting me put my name in but it does the age works fine. I know i can change the order of the statements but is there another way I could do it?

import java.util.Scanner;

public class ScannerErr2
{
  public static void main(String [] args)
  {
    Scanner keyboard= new Scanner(System.in);
    String name;
    int    age;

    System.out.print("Enter your age : ");
    age= keyboard.nextInt();
    System.out.print("Enter your name: ");
    name= keyboard.nextLine();

    System.out.println("Age : "+age);
    System.out.println("Name: "+name);
  }
}

推荐答案

你的问题是下一个 int 没有考虑你名字部分的输入中的换行符.因此名称返回为空白.

You problem is that the next int doesn't consider the new line character which goes in the input for your name part. Hence name is returned as blank.

您可以通过 2 种方式更改代码:

You can change your code in 2 ways:

System.out.print("Enter your age : ");
age = keyboard.nextInt();
keyboard.nextLine();
System.out.print("Enter your name: ");
name = keyboard.nextLine();

或

System.out.print("Enter your age : ");
age = Integer.parseInt(keyboard.nextLine().trim());
System.out.print("Enter your name: ");
name = keyboard.nextLine();

我个人喜欢第二种方式.

I personally like the second way.

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