Java Polymorphism(Java 多态性)
问题描述
This is a question just out of curiosity.
I know that when we call a subclass object's overridden method by the reference of it's superclass, JVM gives importance to the type of object and not to type of reference.
This is my simple code :
class Animal
{
void eat()
{
System.out.println("Animal is eating...");
}
}
class Horse extends Animal
{
@Override
void eat()
{
System.out.println("Horse is eating...");
}
}
public class PolymorphismTest
{
public static void main(String...args)
{
Animal a=new Animal();
a.eat();
Animal h= new Horse();
h.eat();
}
}
As expected, I get the output :
run:
Animal is eating...
Horse is eating...
BUILD SUCCESSFUL (total time: 0 seconds)
Now my question is , Is there any way that we can use reference h to call the superclass eat() method and not the subclass one? I know this is a question that is somewhat against the laws of polymorphism but you never know when the need may arise to do so.
I tried to typecast the reference h to Animal but no luck. Any ideas?
class Horse extends Animal
{
@Override
void eat()
{
super.eat();
}
}
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本文标题为:Java 多态性


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