JSON 类型不匹配或 org.json.jsonecxeption-Java问题

JSON type mismatch or org.json.jsonecxeption(JSON 类型不匹配或 org.json.jsonecxeption)

本文介绍了JSON 类型不匹配或 org.json.jsonecxeption的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

链接是http://iipacademy.in/askpoll/ten_feed.php

异常在 onPostExecute() 方法中(第 4 行):

exception is in onPostExecute() method (4th line) :

Log.i("result", result);
try {
    if (result != null) {
        JSONArray jsonArray = new JSONArray(result); // erreor
        for (int i = 0; i < jsonArray.length(); i++) {
            JSONObject objJson = jsonArray.getJSONObject(i);

            TopTenGetterSetter obj = new TopTenGetterSetter();  


            obj.setQ(objJson.getString("question"));
            obj.setA(objJson.getString("option1"));
            obj.setB(objJson.getString("option2"));
            obj.setC(objJson.getString("option3"));
            obj.setD(objJson.getString("option4"));

            polls.add(obj);
                        }

    }
} catch (JSONException e) {
    e.printStackTrace();
    Toast.makeText(getApplicationContext(), "error",
            Toast.LENGTH_SHORT).show();
}

逻辑猫:

12-18 03:20:45.447: W/System.err(2790): org.json.JSONException: Value response of type java.lang.String cannot be converted to JSONArray
12-18 03:20:45.447: W/System.err(2790):     at org.json.JSON.typeMismatch(JSON.java:111)
12-18 03:20:45.447: W/System.err(2790):     at org.json.JSONArray.<init>(JSONArray.java:91)
12-18 03:20:45.447: W/System.err(2790):     at org.json.JSONArray.<init>(JSONArray.java:103)
12-18 03:20:45.447: W/System.err(2790):     at com.example.askpollie.LatestPollParticipated$FetchingEventsDetails.onPostExecute(LatestPollParticipated.java:188)
12-18 03:20:45.447: W/System.err(2790):     at com.example.askpollie.LatestPollParticipated$FetchingEventsDetails.onPostExecute(LatestPollParticipated.java:1)
12-18 03:20:45.447: W/System.err(2790):     at android.os.AsyncTask.finish(AsyncTask.java:631)
12-18 03:20:45.447: W/System.err(2790):     at android.os.AsyncTask.access$600(AsyncTask.java:177)
12-18 03:20:45.447: W/System.err(2790):     at android.os.AsyncTask$InternalHandler.handleMessage(AsyncTask.java:644)
12-18 03:20:45.447: W/System.err(2790):     at android.os.Handler.dispatchMessage(Handler.java:99)
12-18 03:20:45.447: W/System.err(2790):     at android.os.Looper.loop(Looper.java:137)
12-18 03:20:45.447: W/System.err(2790):     at android.app.ActivityThread.main(ActivityThread.java:5103)
12-18 03:20:45.447: W/System.err(2790):     at java.lang.reflect.Method.invokeNative(Native Method)
12-18 03:20:45.447: W/System.err(2790):     at java.lang.reflect.Method.invoke(Method.java:525)
12-18 03:20:45.447: W/System.err(2790):     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:737)
12-18 03:20:45.447: W/System.err(2790):     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553)
12-18 03:20:45.447: W/System.err(2790):     at dalvik.system.NativeStart.main(Native Method)
12-18 03:20:45.447: D/dalvikvm(2790): GC_FOR_ALLOC freed 5131K, 55% free 4437K/9672K, paused 2ms, total 2ms

Message 是一个数组，那么它的代码应该是什么或者如何解决?

Message is an array so what should be its code or how to can it be solved ?

谢谢在进步 ...

推荐答案

org.json.JSONException: Value response of type java.lang.String cannot be converted to JSONArray

看起来响应是一个字符串而不是一个 json 数组

Looks like response is a string not a json array

{  // json object node 
    "response": { // json object response
        "result": 1,
        "Message": [ // json array Message
            {        // json object node 
                "pollid": "98",
                 "category": "Entertainment",
                 "question": "what",  //  string
                 "option1": "981.mov",

结果是一个json对象而不是json数组

The result is a json object not json array

JSONArray jsonArray = new JSONArray(result);

应该

JSONObject jObj = new JSONObject(result);
JSONObject response = jObj.getJSONObject("response");
//JSONObject jb = new JSONObject(response);
JSONArray jr = response.getJSONArray("Message");
for(int i=0;i<jr.length();i++)
{
JSONObject jb1 = jr.getJSONObject(i);
String question = jb1.getString("question");
Log.i(".......",question);
}

这篇关于JSON 类型不匹配或 org.json.jsonecxeption的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持编程学习网！