Objective-C 中的快速枚举能保证迭代的顺序吗?

Does fast enumeration in Objective-C guarantee the order of iteration?(Objective-C 中的快速枚举能保证迭代的顺序吗?)

问题描述

我可以期望它按顺序从数组的开头到结尾吗?在文档中找不到任何关于此的内容.

Can I expect it to go from the start of an array to the end in order? Can't find anything in the docs about this.

即是

for (id val in array)
{
   NSLog(@"%@", val);
}

总是会打印出相同的结果

always going to print out the same as

for (int i = 0; i < [array count]; ++i)
{
   NSLog(@"%@", [array objectAtIndex:i]);
}

推荐答案

来自 Apple 的 Objective-C 文档 关于快速枚举:

From Apples' Objective-C documentation on fast enumeration:

对于具有明确定义顺序的集合或枚举器(例如从数组派生的 NSArray 或 NSEnumerator 实例)，枚举按该顺序进行，因此如果需要，只需计算迭代次数即可为您提供正确的集合索引.

For collections or enumerators that have a well-defined order—such as NSArray or NSEnumerator instance derived from an array—the enumeration proceeds in that order, so simply counting iterations will give you the proper index into the collection if you need it.

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