学说 dbal 查询构建器作为准备好的语句

doctrine dbal querybuilder as prepared statement(学说 dbal 查询构建器作为准备好的语句)

问题描述

我正在尝试创建一个 Doctrine DBAL 查询构建器对象并在其中设置一个参数.(使用 postgres db，dbal 2.3.4，学说

I'm trying to create a Doctrine DBAL querybuilder object and setting a parameter in it. (using a postgres db, dbal 2.3.4, doctrine

$connection = $this->_em->getConnection();
$qb = $connection->createQueryBuilder();
$qb->select('tbl_user_contract.pkid AS pkid');
$qb->from('tbl_user_contract', 'tbl_user_contract');
$qb->join('tbl_user_contract', 'tbl_user', 'tbl_user', 'tbl_user_contract.fk_user = tbl_user.pkid');
$qb->where('tbl_user.pkid = :userid');
$qb->setParameter(':userid', 10);

当我尝试获取此 querybuilder 对象的结果时，出现以下错误:

When I try to get the results of this querybuilder object I get the following error:

SQLSTATE[08P01]: <<Unknown error>>: 7 ERROR: bind message supplies 0 parameters, 
but prepared statement "pdo_stmt_00000002" requires 1

当我检查 postgres 日志时，我看到查询通过，我注意到它需要一个参数，但我不会得到传入的参数.

When I check the postgres logs, I see the query passing by and I notice that it expects a parameter, but I won't get a parameter passed in.

我尝试在 where 表达式本身中设置 id(不使用准备好的语句)，这奏效了.但我真的很想通过准备好的语句来实现这一点.

I tried to set the id in the where expression itself (without using prepared statements), that worked. But I really want to get this working with prepared statements.

有人知道如何解决这个问题吗?

Anyone knows how to solve this?

提前致谢

推荐答案

我认为你只需要从 setparameter 命令中删除冒号

I think you just need to remove colon from setparameter command

$qb->setParameter('userid', 10);

至少它适用于 Doctrine help https://www.doctrine-project.org/projects/doctrine-dbal/en/2.9/reference/query-builder.html

At least it works in Doctrine help https://www.doctrine-project.org/projects/doctrine-dbal/en/2.9/reference/query-builder.html

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