When asyncio task gets stored after creation, exceptions from task get muted(当异步任务在创建后存储时,任务中的异常将被静音)
本文介绍了当异步任务在创建后存储时,任务中的异常将被静音的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我在项目中使用Asyncio时遇到此奇怪行为。
import asyncio
def schedule_something():
global f
tsk = asyncio.async(do_something())
f = tsk #If this line is commented out, exceptions can be heard.
@asyncio.coroutine
def do_something():
raise Exception()
loop = asyncio.get_event_loop()
loop.call_soon(schedule_something)
loop.run_forever()
loop.close()
出于某种原因,调用asyncio.async()
时存储结果任务会阻止异常执行任何操作。
有没有人能说明一下这种情况?我需要一种方法来捕获当前项目中的异常。
推荐答案
这是因为只有在未检索其结果的情况下销毁Task
时才会引发异常。当您将Task
赋给全局变量时,它将始终具有活动引用,因此永远不会被销毁。asyncio/futures.py中有一个文档字符串详细介绍了这一点:
class _TracebackLogger:
"""Helper to log a traceback upon destruction if not cleared.
This solves a nasty problem with Futures and Tasks that have an
exception set: if nobody asks for the exception, the exception is
never logged. This violates the Zen of Python: 'Errors should
never pass silently. Unless explicitly silenced.'
However, we don't want to log the exception as soon as
set_exception() is called: if the calling code is written
properly, it will get the exception and handle it properly. But
we *do* want to log it if result() or exception() was never called
-- otherwise developers waste a lot of time wondering why their
buggy code fails silently.
An earlier attempt added a __del__() method to the Future class
itself, but this backfired because the presence of __del__()
prevents garbage collection from breaking cycles. A way out of
this catch-22 is to avoid having a __del__() method on the Future
class itself, but instead to have a reference to a helper object
with a __del__() method that logs the traceback, where we ensure
that the helper object doesn't participate in cycles, and only the
Future has a reference to it.
The helper object is added when set_exception() is called. When
the Future is collected, and the helper is present, the helper
object is also collected, and its __del__() method will log the
traceback. When the Future's result() or exception() method is
called (and a helper object is present), it removes the the helper
object, after calling its clear() method to prevent it from
logging.
如果要查看/处理异常,只需使用add_done_callback
来处理任务结果,并在出现异常时执行所需操作:
import asyncio
def handle_result(fut):
if fut.exception():
fut.result() # This will raise the exception.
def schedule_something():
global f
tsk = asyncio.async(do_something())
tsk.add_done_callback(handle_result)
f = tsk
@asyncio.coroutine
def do_something():
raise Exception()
loop = asyncio.get_event_loop()
loop.call_soon(schedule_something)
loop.run_forever()
loop.close()
这篇关于当异步任务在创建后存储时,任务中的异常将被静音的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
沃梦达教程
本文标题为:当异步任务在创建后存储时,任务中的异常将被静音


猜你喜欢
- 如何在 python3 中将 OrderedDict 转换为常规字典 2022-01-01
- python check_output 失败,退出状态为 1,但 Popen 适用于相同的命令 2022-01-01
- 如何将一个类的函数分成多个文件? 2022-01-01
- 沿轴计算直方图 2022-01-01
- padding='same' 转换为 PyTorch padding=# 2022-01-01
- 使用Heroku上托管的Selenium登录Instagram时,找不到元素';用户名'; 2022-01-01
- 分析异常:路径不存在:dbfs:/databricks/python/lib/python3.7/site-packages/sampleFolder/data; 2022-01-01
- 如何在 Python 的元组列表中对每个元组中的第一个值求和? 2022-01-01
- pytorch 中的自适应池是如何工作的? 2022-07-12
- python-m http.server 443--使用SSL? 2022-01-01