using System;class MyApplication {static int count(bool []myArr, int num) {int myCount = 0, res = 0;for (int i = 0; i num; i++) {
编程学习网为您整理以下代码实例,主要实现:C#检查是否有N个连续二进制数,希望可以帮到各位朋友。
using System;
class MyApplication {
static int count(bool []myArr, int num) {
int myCount = 0, res = 0;
for (int i = 0; i < num; i++) {
if (myArr[i] == false)
myCount = 0;
else {
myCount++;
res = Math.Max(res, myCount);
}
}
return res;
}
public static voID Main() {
bool []myArr = {false, true, false, false, false, true, true, true};
int num = myArr.Length;
Console.Write("Consecutive 1's = "+count(myArr, num));
}
}
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本文标题为:C#检查是否有N个连续二进制数


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